Advertisements
Advertisements
प्रश्न
Calculate the number of atoms of each kind in 5.3 grams of sodium carbonate.
Advertisements
उत्तर
Molecular mass of Na2CO3 = 106 g
106 g has 2 x 6.02 x 1023 x 2 atoms of Na
So, 5.3g will have = `(6.02 xx 10^23 xx 2)/106 xx 5.3`
= 6.022 x 1022 atoms
Number of carbon atoms = `(6.02 xx 10^23)/106 xx53/10`
= 3.01 x 1022 atoms
And number of oxygen atoms = `(3 xx 6.02 xx 10^23)/106 xx 53/10`
= 9.03 x 1022
संबंधित प्रश्न
Aluminium carbide reacts with water according to the following equation :
`Al_4C_3 + 12H_2O-> 4Al(OH)_3 + 3CH_4`
1)What mass of aluminium hydroxide is formed from 12g of aluminium carbide?
2) What volume of methane at s.t.p. is obtained from 12g of aluminium carbide?
[Relatively molecular weight of `Al_4Cl_3 = 144; Al(OH)_3 = 78]`
Calculate the relative molecular mass of Chloroform.
(use K = 39, Cl = 35.5, O = 16, C = 12, H = 1, Na = 23, N = 14, S= 32)
Calculate the relative molecular mass of Ammonium sulphate.
(use K = 39, Cl = 35.5, O = 16, C = 12, H = 1, Na = 23, N = 14, S= 32)
Calculate the percentage of water in ferrous sulphate crystals.
[Fe = 56, S = 32, O =16, H = 1].
Calculate the percentage of phosphorous in the fertilizer superphosphate, Ca(H2PO4)2. [Ca = 40, H =1, P =31, O = 16] (Correct to 1 decimal place)
The reaction of potassium permanganate (VII) with acidified iron (II) sulphate is given below:
2KMno4 + 10FeSO4 + 8H2O → K2SO4 + 2MnSO4 + 5Fe2(SO4)3 + 8H2O
If 15.8g of potassium permanganate (VII) was used in the reaction, calculate the mass of iron (II) sulphate used in the above reaction.
Calculate the relative molecular mass of:
CHCl3
Find the weight of 0.5 mole of O2.
The atomic mass of Chlorine is 35.5. What is its vapour density?
Ammonia burns in oxygen and the combustion, in the presence of a catalyst, may be represented by;
\[\ce{2NH3 + 2 1/2O2 -> 2NO + 3H2O}\] [H = 1, N = 14, O = 16]
What mass of steam is produced when 1.5 g of nitrogen monoxide is formed?
