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The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and - Physics

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Question

The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when

  1. the key K is open, and
  2. the key K is closed

Numerical
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Solution

ε = 4 volt

r = 2 ohm

R = 8 Ω

V = ?

I = ?

  1. When key is open: Since there will be no current flowing through the circuit, the voltmeter reads zero (A = 0) and the electromotive force (e.m.f.) of the cell is two volts.
  2. When key is closed:
    `I = ε/("R" + r)`
    = `(4 " volt")/(8 + 2)`
    = `4/10`
    = 0.4 A
    Ammeter reading = 0.4 A
    `"R" = "V"/"I"` or V = IR
    V = 0.4 × 8
    = 3.2 volt
    voltmeter reading = 3.2 volt
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Chapter 8: Current Electricity - EXERCISE - 8(B) [Page 201]

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Selina Physics [English] Class 10 ICSE
Chapter 8 Current Electricity
EXERCISE - 8(B) | Q 1. | Page 201

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