हिंदी

The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and

Advertisements
Advertisements

प्रश्न

The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when

  1. the key K is open, and
  2. the key K is closed

संख्यात्मक
Advertisements

उत्तर

ε = 4 volt

r = 2 ohm

R = 8 Ω

V = ?

I = ?

  1. When key is open: Since there will be no current flowing through the circuit, the voltmeter reads zero (A = 0) and the electromotive force (e.m.f.) of the cell is two volts.
  2. When key is closed:
    `I = ε/("R" + r)`
    = `(4 " volt")/(8 + 2)`
    = `4/10`
    = 0.4 A
    Ammeter reading = 0.4 A
    `"R" = "V"/"I"` or V = IR
    V = 0.4 × 8
    = 3.2 volt
    voltmeter reading = 3.2 volt
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Current Electricity - EXERCISE - 8(B) [पृष्ठ २०१]

APPEARS IN

सेलिना Concise Physics Part 2 [English] Class 10 ICSE
अध्याय 8 Current Electricity
EXERCISE - 8(B) | Q 1. | पृष्ठ २०१

संबंधित प्रश्न

What happens to the resistivity of semiconductor with the increase of temperature?


Name two factors on which the internal resistance of a cell depends and state how does it depend on the factors stated by you.


Explain why the p.d across the terminals of a cell is more in an open circuit and reduced in a closed circuit. 


A battery of e.m.f 3.0 V supplies current through a circuit in which the resistance can be changed.
A high resistance voltmeter is connected across the battery. When the current is 1.5 A, the voltmeter reads 2.7 V. Find the internal resistance of the battery. 


A cell of e.m.f. 1.8V and internal resistance 2Ω is connected in series with an ammeter of resistance 0.7Ω and a resistor of 4.5Ω as shown in Fig. 

  1. What would be the reading of the ammeter?
  2. What is the potential difference across the terminals of the cell? 

A battery of e.m.f. 15 V and internal resistance 3 ohm is connected to two resistors of resistances 3 ohm and 6 ohm is series Find:
(a) the current through the battery
(b) the p.d. between the terminals of the battery. 


A cell of e.m.f. ε and internal resistance 𝔯 sends current 1.0 A when it is connected to an external resistance 1.9 Ω. But it sends current 0.5 A when it is connected to an external resistance 3.9 Ω. Calculate the values of ε and 𝔯.


Four cells each of e.m.f. 2V and internal resistance 0.1 Ω are connected in series to an ammeter of negligible resistance, a 1.6 Ω resistor and an unknown resistor R1. The current in the circuit is 2A. Draw a labelled diagram and calculate:

(i) Total resistance of the circuit,
(ii) Total e.m.f.
(iii) The value of R1 and
(iv) The p.d. across R1.


Explain the meaning of the term internal resistance of a cell.


A battery of e.m.f. 6.0 V supplies current through a circuit in which the resistance can be changed. A high resistance voltmeter is connected across the battery. When the current is 3 A, the voltmeter reads 5.4 V. Find the internal resistance of the battery.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×