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प्रश्न
Four cells each of e.m.f. 2V and internal resistance 0.1 Ω are connected in series to an ammeter of negligible resistance, a 1.6 Ω resistor and an unknown resistor R1. The current in the circuit is 2A. Draw a labelled diagram and calculate:
(i) Total resistance of the circuit,
(ii) Total e.m.f.
(iii) The value of R1 and
(iv) The p.d. across R1.
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उत्तर
(i) The resistance in the circuit
= (1.6 + 4 × 0.1 + R1) Ω
= (2 + R1) Ω
(ii) Total e.m.f. = No. of cell × e.m.f. of each cell = 4 × 2 = 8 V
(iii) Current in main circuit i = `"Total e.m.f."/"Total resistance"`
or 2 = `8/(2 + "R"_1)`
∴ R1 = `4/2 = 2` Ω
(iv) The p.d. across R1 = V = i R1 = 2 × 2 = 4V
संबंधित प्रश्न
Name two factors on which the internal resistance of a cell depends and state how does it depend on the factors stated by you.
A cell of e.m.f ε and internal resistance r is used to send current to an external resistance R. Write expressions for
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- the current drawn from the cell.
- the p.d. across the cell.
- voltage drop inside the cell.
A cell is used to send current to an external circuit.
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- Under what condition is the e.m.f. of a cell equal to its terminal voltage?
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voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when (i) the key K is open, (ii) the key K is closed.
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(ii) The current flowing in the external circuit.
(iii) The drop in potential across-the terminals of the cells.
Define the e.m.f. (E) of a cell and the potential difference (V) of a resistor R in terms of the work done in moving a unit charge. State the relation between these two works and the work done in moving a unit charge through a cell connected across the resistor. Take the internal resistance of the cell as ‘r’. Hence obtain an expression for the current i in the circuit.
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- Calculate the current drawn from the cell.
- State whether the current through 10 Ω resistor is greater than, less than or equal to the current through the 12 Ω resistor.
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- the key K is open, and
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