मराठी

The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and

Advertisements
Advertisements

प्रश्न

The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when

  1. the key K is open, and
  2. the key K is closed

संख्यात्मक
Advertisements

उत्तर

ε = 4 volt

r = 2 ohm

R = 8 Ω

V = ?

I = ?

  1. When key is open: Since there will be no current flowing through the circuit, the voltmeter reads zero (A = 0) and the electromotive force (e.m.f.) of the cell is two volts.
  2. When key is closed:
    `I = ε/("R" + r)`
    = `(4 " volt")/(8 + 2)`
    = `4/10`
    = 0.4 A
    Ammeter reading = 0.4 A
    `"R" = "V"/"I"` or V = IR
    V = 0.4 × 8
    = 3.2 volt
    voltmeter reading = 3.2 volt
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Current Electricity - EXERCISE - 8(B) [पृष्ठ २०१]

APPEARS IN

सेलिना Concise Physics [English] Class 10 ICSE
पाठ 8 Current Electricity
EXERCISE - 8(B) | Q 1. | पृष्ठ २०१

संबंधित प्रश्‍न

What happens to the resistivity of semiconductor with the increase of temperature?


A cell of Emf 2 V and internal resistance 1.2 Ω is connected with an ammeter of resistance 0.8 Ω and two resistors of 4.5 Ω and 9 Ω as shown in the diagram below:

1) What would be the reading on the Ammeter?

2) What is the potential difference across the terminals of the cell?


A cell of e.m.f ε and internal resistance r is used to send current to an external resistance R. Write expressions for

  1. the total resistance of circuit.
  2. the current drawn from the cell.
  3. the p.d. across the cell.
  4. voltage drop inside the cell. 

Explain why the p.d across the terminals of a cell is more in an open circuit and reduced in a closed circuit. 


A cell is used to send current to an external circuit.

  1. How does the voltage across its terminals compare with its e.m.f.?
  2. Under what condition is the e.m.f. of a cell equal to its terminal voltage? 

The diagram below in Fig. 8.40 shows a cell of e.m.f. ε = 2 volt and internal resistance r = 1 ohm to an external resistance R = 4 ohm. The ammeter A measures the current in the circuit and the
voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when (i) the key K is open, (ii) the key K is closed. 

  


A cell of emf. 1.5 V and internal resistance 10 ohms is connected to a resistor of 5 ohms, with an ammeter in series see fig.. What is the reading of the ammeter?


Four cells, each of e.m.f. 1.5 V and internal resistance 2.0 ohms are connected in parallel. The battery of cells is connected to an external resistance of 2.5 ohms. Calculate:

(i) The total resistance of the circuit.
(ii) The current flowing in the external circuit.
(iii) The drop in potential across-the terminals of the cells.


Four cells each of e.m.f. 2V and internal resistance 0.1 Ω are connected in series to an ammeter of negligible resistance, a 1.6 Ω resistor and an unknown resistor R1. The current in the circuit is 2A. Draw a labelled diagram and calculate:

(i) Total resistance of the circuit,
(ii) Total e.m.f.
(iii) The value of R1 and
(iv) The p.d. across R1.


Study the diagram:

  1. Calculate the total resistance of the circuit.
  2. Calculate the current drawn from the cell.
  3. State whether the current through 10 Ω resistor is greater than, less than or equal to the current through the 12 Ω resistor.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×