मराठी

A Cell Supplies a Current of 0.6 a Through a 2ω Coil and a Current of 0.3 a Through on 8ω Coil. Calculate the E.M.F and Internal Resistnce of the Cell.

Advertisements
Advertisements

प्रश्न

A cell supplies a current of 0.6 A through a 2Ω coil and a current of 0.3 A through on 8Ω coil. Calculate the e.m.f and internal resistance of the cell.

टीपा लिहा
Advertisements

उत्तर

Given: I1 = 0.6 A, R1 = 2 Ω and I2 = 0.3 A, R2 = 8 Ω

Let the e.m.f. of the cell is E and its internal resistance is r.

From I = `"E"/("R + r")`

0.6 = `"E"/("2 + r")` and `0.3 = "E"/("8 + r")`

∴ E = 0.6 (2 + r) = 1.2 + 0.6 r and

E = 0.3 (8 + r) = 2.4 + 0.3r

Thus, 1.2 + 0.6r = 2.4 + 0.3r

or 0.6r - 0.3r = 2.4 - 1.2

Or 0.3 r = 1.2  or

r = `1.2/0.3 = 4 Omega`.

and E = 1.2 + 0.6 × 4 = 1.2 + 2.4 = 3.6 V

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

A cell of Emf 2 V and internal resistance 1.2 Ω is connected with an ammeter of resistance 0.8 Ω and two resistors of 4.5 Ω and 9 Ω as shown in the diagram below:

1) What would be the reading on the Ammeter?

2) What is the potential difference across the terminals of the cell?


A cell of e.m.f ε and internal resistance r is used to send current to an external resistance R. Write expressions for

  1. the total resistance of circuit.
  2. the current drawn from the cell.
  3. the p.d. across the cell.
  4. voltage drop inside the cell. 

A cell is used to send current to an external circuit.

  1. How does the voltage across its terminals compare with its e.m.f.?
  2. Under what condition is the e.m.f. of a cell equal to its terminal voltage? 

A cell of emf. 1.5 V and internal resistance 10 ohms is connected to a resistor of 5 ohms, with an ammeter in series see fig.. What is the reading of the ammeter?


A battery of 4 cell, each of e.m.f. 1.5 volt and internal resistance 0.5 Ω is connected to three resistances as shown in the figure. Calculate:
(i) The total resistance of the circuit.
(ii) The current through the cell.
(iii) The current through each resistance.
(iv) The p.d. across each resistance.


Four cells each of e.m.f. 2V and internal resistance 0.1 Ω are connected in series to an ammeter of negligible resistance, a 1.6 Ω resistor and an unknown resistor R1. The current in the circuit is 2A. Draw a labelled diagram and calculate:

(i) Total resistance of the circuit,
(ii) Total e.m.f.
(iii) The value of R1 and
(iv) The p.d. across R1.


When a resistance of 3Ω is connected across a cell, the current flowing is 0.5 A. On changing the resistance to 7Ω, the current becomes 0.25A. Calculate the e.m.f. and the internal resistance of the cell.


(a) Calculate the total resistance across AB.

(b) If a cell of e.m.f 2.4 V with negligible internal resistance is connected across AB then calculate the current drawn from the cell.


Explain the meaning of the term internal resistance of a cell.


The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when

  1. the key K is open, and
  2. the key K is closed


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×