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Question
Suppose the tube in the previous problem is kept vertical with B upward. Water enters through B at the rate of 1 cm3/s. Repeat parts (a), (b) and (c). Note that the speed decreases as the water falls down.
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Solution
Water enters through B at the rate of 1 cm3s−1.
(a) Speed of water at A,
\[\vec{V}_A = 25 cm/s\]v
(b) Speed of water at B,
\[\vec{V}_B = 50 cm/s\]
(c) By Bernoulli’s equation, we have:
`1/2ρv_A^2 + ρgh_A + P_A = 1/2ρvB^2 + ρgh_B + P_B`
`=> P_A - P_B = 1/2 × 1 × 1875 + 1/2 × 1000 × 15/16`
= 1875 dyn /cm2
= 188 N/m2
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