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Question
Suppose the tube in the previous problem is kept vertical with A upward but the other conditions remain the same. the separation between the cross sections at A and B is 15/16 cm. Repeat parts (a), (b) and (c) of the previous problem. Take g = 10 m/s2.
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Solution
Given:
Separation between the cross sections at A and B = 15/16 cm
Speed of water at A, vA = 25 cm/s
Speed of water at B, vB = 50 cm/s
(c) By Bernoulli's equation, we get:
`1/2pv_A^2+ρgh_A+P_A=1/2pv_B^2+ρgh_B+P_B`
`=>P_A-P_B=(1/2)p(v_B^2-v_A^2)+pg(h_B-h_A) [h_A-h_B=(15/16)cm]`
`=>P_A-P_B=1/2(2500-625)-1000×15/16`
= 0
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