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Question
Sulphur hexafluoride is a colourless, odourless gas; calculate the pressure exerted by 1.82 moles of the gas in a steel vessel of volume 5.43 dm3 at 69.5 °C, assuming ideal gas behaviour
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Solution
n = 1.82 mole
V = 5.43 dm3
T = 69.5 + 273 = 342.5
P = ?
PV = nRT
P = `"nRT"/"V"`
P = `(1.82 "mol" xx 0.0821 "dm"^3 "atm mol"^-1 "K"^-1 xx 342.5 "K")/(5.43 "dm"^3)`
P = 9.425 atm
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