Advertisements
Advertisements
Question
Solve:
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Advertisements
Solution
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Let `x/(x + 2) = y`
Then y2 – 7y + 12 = 0
`=>` y2 – 4y – 3y + 12 = 0
`=>` y(y – 4) – 3(y – 3) = 0
`=>` (y – 4)(y – 3) = 0
Then y = 4 and y = 3
`=> x/(x + 2) = 4` and `x/(x + 2) = 3`
`=> 4x + 8 = x` and `3x + 6 = x`
`=> x = (-8)/3` and `x = -3`
RELATED QUESTIONS
Solve the following quadratic equations by factorization:
25x(x + 1) = – 4
Solve the following quadratic equations by factorization:
`(x + 3)/(x + 2) = (3x - 7)/(2x - 3); x ≠ -2, 3/2`
The sum of a natural number and its positive square root is 132. Find the number.
Solve the following quadratic equation by
factorisation.
5m2 = 22m + 15
If 2 is a root of the equation x2 + bx + 12 = 0 and the equation x2 + bx + q = 0 has equal roots, then q =
If one of the equation ax2 + bx + c = 0 is three times times the other, then b2 : ac =
Solve equation using factorisation method:
x2 – 10x – 24 = 0
Solve equation using factorisation method:
2x2 – 9x + 10 = 0, when:
- x ∈ N
- x ∈ Q
Solve the following equation by factorization
3(x – 2)2 = 147
The product of two successive integral multiples of 5 is 300. Then the numbers are:
