Advertisements
Advertisements
Question
Solve:
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Advertisements
Solution
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Let `x/(x + 2) = y`
Then y2 – 7y + 12 = 0
`=>` y2 – 4y – 3y + 12 = 0
`=>` y(y – 4) – 3(y – 3) = 0
`=>` (y – 4)(y – 3) = 0
Then y = 4 and y = 3
`=> x/(x + 2) = 4` and `x/(x + 2) = 3`
`=> 4x + 8 = x` and `3x + 6 = x`
`=> x = (-8)/3` and `x = -3`
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equation for x: x2 – 2ax – (4b2 – a2) = 0
Find the roots of the following quadratic equation by factorisation:
2x2 + x – 6 = 0
Solve the following quadratic equations by factorization:
`(x + 3)/(x - 2) - (1 - x)/x = 17/4; x ≠ 0, 2`
The difference of two numbers is 4. If the difference of their reciprocals is `4/21`, find the numbers.
Solve the following quadratic equations by factorization:
`2(x^2 – 6) = 3 ( x – 4)`
The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.
A shopkeeper purchases a certain number of books for Rs. 960. If the cost per book was Rs. 8 less, the number of books that could be purchased for Rs. 960 would be 4 more. Write an equation, taking the original cost of each book to be Rs. x, and Solve it to find the original cost of the books.
There are three consecutive positive integers such that the sum of the square of the first and the product of other two is 154. What are the integers?
The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find the present age.
By selling an article for Rs. 21, a trader loses as much per cent as the cost price of the article. Find the cost price.
