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Question
Solve x2 – 4x – 12 =0; when x ∈ I
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Solution
x2 – 4x – 12 =0
`=> x^2 - 6x + 2x - 12 = 0`
`=> x(x - 6) + 2(x - 6) = 0`
=> (x - 6)(x + 2) = 0
then x = 6 and x = -2
Since `x in I` then x = 6 and -2
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