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Three Years Ago, a Man Was 5 Times the Age of His Son. Four Years Hence, He Will Be Thrice His Son'S Age. Find the Present Ages of the Man and His Son. - Mathematics

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Question

Three years ago, a man was 5 times the age of his son. Four years hence, he will be thrice his son's age. Find the present ages of the man and his son.

Sum
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Solution

Let the present age of the man be M years and his sons age be S years. 

Then, as per the question description, 

M - 3 = 5 (S-3 ) ...... (i) 

M + 4 =3 (S+4 ) ...... (ii) 

From (i), we get: M + 12 = 5 S 

⇒ S = `("M" + 12)/5`  .........(iii)

From (ii), we get: M - 8 = 3S

Putting (iii) above, we get: M - 8 = `(3 (M + 12))/5`

⇒ 5M - 40 = 3M + 36 

⇒  2M = 76 

⇒ M =38 years and hence,  S= 10 years 

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Chapter 7: Problems Based On Quadratic Equations - Exercise 7.1

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Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 7 Problems Based On Quadratic Equations
Exercise 7.1 | Q 18
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