Advertisements
Advertisements
Question
Solve the following equation: `7"x" + 3/"x" = 35 3/5`
Advertisements
Solution
`7"x" + 3/"x" = 35 3/5`
`7"x"^2 + 3 = 178/5 "x"`
`7"x"^2 - 178/5 "x" + 3 = 0`
`"x"^2 - 178/35 "x" + 3/7 = 0`
`"x"^2 - 5"x" - 3/35 "x" + 3/7 = 0`
`"x"("x" - 5) - 3/35 ("x" - 5) = 0`
`("x" - 5)("x" - 3/35) = 0`
x = 5 , x = `3/35`
APPEARS IN
RELATED QUESTIONS
Solve for x
:`1/((x-1)(x-2))+1/((x-2)(x-3))=2/3` , x ≠ 1,2,3
Solve the following quadratic equation for x:
`x^2+(a/(a+b)+(a+b)/a)x+1=0`
Find the roots of the following quadratic equation by factorisation:
100x2 – 20x + 1 = 0
Solve the following quadratic equations by factorization:
`m/nx^2+n/m=1-2x`
Solve the following quadratic equations by factorization:
`(x-3)/(x+3 )+(x+3)/(x-3)=2 1/2`
Find two consecutive multiples of 3 whose product is 648.
Solve the following quadratic equations by factorization: \[\frac{x + 1}{x - 1} + \frac{x - 2}{x + 2} = 4 - \frac{2x + 3}{x - 2}; x \neq 1, - 2, 2\]
Solve the following equation:
`("x" + 1)/("x" - 1) - ("x" - 1)/("x" + 1) = 5/6 , "x" ≠ -1,1`
The present age of the mother is square of her daughter's present age. 4 years hence, she will be 4 times as old as her daughter. Find their present ages.
In each of the following, determine whether the given values are solution of the given equation or not:
`x = 1/x = (13)/(6), x = (5)/(6), x = (4)/(3)`
