Advertisements
Advertisements
प्रश्न
Solve:
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Advertisements
उत्तर
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Let `x/(x + 2) = y`
Then y2 – 7y + 12 = 0
`=>` y2 – 4y – 3y + 12 = 0
`=>` y(y – 4) – 3(y – 3) = 0
`=>` (y – 4)(y – 3) = 0
Then y = 4 and y = 3
`=> x/(x + 2) = 4` and `x/(x + 2) = 3`
`=> 4x + 8 = x` and `3x + 6 = x`
`=> x = (-8)/3` and `x = -3`
संबंधित प्रश्न
Solve the following quadratic equations
(i) x2 + 5x = 0 (ii) x2 = 3x (iii) x2 = 4
Solve the following quadratic equations by factorization:
`(x+1)/(x-1)-(x-1)/(x+1)=5/6` , x ≠ 1, x ≠ -1
The perimeter of a rectangular field is 82 m and its area is 400 m2. Find the breadth of the rectangle.
If the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360. Find the original price of the toy.
Solve for x: `3x^2-2sqrt3x+2=0`
In the following determine the set of values of k for which the given quadratic equation has real roots: \[2 x^2 + x + k = 0\]
If a and b are roots of the equation x2 + ax + b = 0, then a + b =
Solve: x(x + 1) (x + 3) (x + 4) = 180.
In each of the following, determine whether the given values are solution of the given equation or not:
x2 + x + 1 = 0; x = 0; x = 1
Find two consecutive even natural numbers such that the sum of their squares is 340.
