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प्रश्न
Solve:
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
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उत्तर
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Let `x/(x + 2) = y`
Then y2 – 7y + 12 = 0
`=>` y2 – 4y – 3y + 12 = 0
`=>` y(y – 4) – 3(y – 3) = 0
`=>` (y – 4)(y – 3) = 0
Then y = 4 and y = 3
`=> x/(x + 2) = 4` and `x/(x + 2) = 3`
`=> 4x + 8 = x` and `3x + 6 = x`
`=> x = (-8)/3` and `x = -3`
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