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Question
Solve the following equation by factorization
x(2x + 5) = 3
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Solution
x(2x + 5) = 3
⇒ 2x2 + 5x - 3 = 0
⇒ 2x2 + 6x - x - 3 = 0
⇒ 2x (x + 3) - 1 (x + 3) = 0
⇒ (x + 3) (2x - 1) = 0
Either x + 3 = 0,
then x = -3
or
2x - 1 = 0,
then 2x = 1
⇒ x = `(1)/(2)`
∴ x = `-3, (1)/(2)`.
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