Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
x(2x + 5) = 3
Advertisements
उत्तर
x(2x + 5) = 3
⇒ 2x2 + 5x - 3 = 0
⇒ 2x2 + 6x - x - 3 = 0
⇒ 2x (x + 3) - 1 (x + 3) = 0
⇒ (x + 3) (2x - 1) = 0
Either x + 3 = 0,
then x = -3
or
2x - 1 = 0,
then 2x = 1
⇒ x = `(1)/(2)`
∴ x = `-3, (1)/(2)`.
APPEARS IN
संबंधित प्रश्न
Solve for x :
`1/(2x - 3) + 1/(x - 5) = 1 1/9 , X != 3/2, 5`
Solve the following quadratic equations by factorization:
`(x+3)/(x-2)-(1-x)/x=17/4`
Solve:
(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0
Write the number of real roots of the equation x2 + 3 |x| + 2 = 0.
Find two consecutive natural numbers whose squares have the sum 221.
Solve the following equation by factorization
x (2x + 1) = 6
In a P.T. display, 480 students are arranged in rows and columns. If there are 4 more students in each row than the number of rows, find the number of students in each row.
Solve the quadratic equation by factorisation method:
x2 – 15x + 54 = 0
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
The product of two integers is –18; the integers are ______.
