English
Maharashtra State BoardSSC (English Medium) 9th Standard

Solve the following simultaneous equation. x - 2y = -1 ; 2x - y = 7 - Algebra

Advertisements
Advertisements

Question

Solve the following simultaneous equation.

x - 2y = -1 ; 2x - y = 7

Sum
Advertisements

Solution

x - 2y = -1    ...(I)

2x - y  = 7      ...(II)

Multiply (I) with 2,

2x - 4y = -2     ....(III)

Subtracting (III) from (II)

2x - y  = 7
2x - 4y = -2
-     +         +   
3y = 9

∴ y = 3

Putting the value of y in (I) we get,

∴ x - 2y = -1

⇒  x - 2 × 3 = -1

⇒ x - 6 = -1

⇒ x = -1 + 6

⇒ x = 5

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Linear Equations in Two Variables - Problem Set 5 [Page 91]

APPEARS IN

Balbharati Mathematics 1 [English] Standard 9 Maharashtra State Board
Chapter 5 Linear Equations in Two Variables
Problem Set 5 | Q (2) (ii) | Page 91

RELATED QUESTIONS

Solve the following system of linear equations by using the method of elimination by equating the coefficients: 3x + 4y = 25 ; 5x – 6y = – 9


Solve for x and y : `\frac { ax }{ b } – \frac { by }{ a } = a + b ; ax – by = 2ab`


Solve (a – b) x + (a + b) y = `a^2 – 2ab – b^2 (a + b) (x + y) = a^2 + b^2`


Two types of boxes A, B are to be placed in a truck having a capacity of 10 tons. When 150 boxes of type A and 100 boxes of type B are loaded in the truck, it weighes 10 tons. But when 260 boxes of type A are loaded in the truck, it can still accommodate 40 boxes of type B, so that it is fully loaded. Find the weight of each type of box.


Sanjay gets fixed monthly income. Every year there is a certain increment in his salary. After 4 years, his monthly salary was Rs. 4500 and after 10 years his monthly salary became 5400 rupees, then find his original salary and yearly increment.


Solve the following simultaneous equation.

x + y = 11 ; 2x - 3y = 7 


Solve the following simultaneous equation.

x − 2y = −2 ; x + 2y = 10 


Solve the following simultaneous equation.

`x/3 + y/4 = 4; x/2 - y/4 = 1`


Solve the following simultaneous equation.

`x/3 + 5y = 13 ; 2x + y/2 = 19`


Solve the following simultaneous equation.

`2/x + 3/y = 13` ; `5/x - 4/y = -2`


By equating coefficients of variables, solve the following equation.

5x + 7y = 17 ; 3x - 2y = 4


By equating coefficients of variables, solve the following equation.

4x + y = 34 ; x + 4y = 16 


A fraction becomes `1/3` when 2 is subtracted from the numerator and it becomes `1/2` when 1 is subtracted from the denominator. Find the fraction.


A fraction becomes `(1)/(3)` when 2 is subtracted from the numerator and it becomes `(1)/(2)` when 1 is subtracted from the denominator. Find the fraction.


If 52x + 65y = 183 and 65x + 52y = 168, then find x + y = ?


Complete the activity.


Evaluate: (1004)3


Read the following passage:

Two schools 'P' and 'Q' decided to award prizes to their students for two games of Hockey ₹ x per student and Cricket ₹ y per student. School 'P' decided to award a total of ₹ 9,500 for the two games to 5 and 4 Students respectively; while school 'Q' decided to award ₹ 7,370 for the two games to 4 and 3 students respectively.

Based on the above information, answer the following questions:

  1. Represent the following information algebraically (in terms of x and y).
  2. (a) What is the prize amount for hockey?
    OR
    (b) Prize amount on which game is more and by how much?
  3. What will be the total prize amount if there are 2 students each from two games?

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×