Advertisements
Advertisements
Question
By equating coefficients of variables, solve the following equations.
3x - 4y = 7; 5x + 2y = 3
Advertisements
Solution
3x - 4y = 7 ...(I)
5x + 2y = 3 ...(II)
Multiply (II) with 2
10x + 4y = 6 ...(III)
Adding (I) and (III)
3x - 4y = 7
10x + 4y = 6
13x = 13
⇒ x = 1
Putting the value of x in (I) we get
∴ 3x - 4y = 7
⇒ 3 × 1 - 4y = 7
⇒ 3 - 4y = 7
⇒ y = -1
Thus, x = 1 and y = -1
APPEARS IN
RELATED QUESTIONS
Solve the following system of linear equations by applying the method of elimination by equating the coefficients
(i)4x – 3y = 4
2x + 4y = 3
(ii)5x – 6y = 8
3x + 2y = 6
Solve the following system of equations: 15x + 4y = 61; 4x + 15y = 72
Solve the following system of equations by using the method of elimination by equating the co-efficients.
`\frac { x }{ y } + \frac { 2y }{ 5 } + 2 = 10; \frac { 2x }{ 7 } – \frac { 5 }{ 2 } + 1 = 9`
Solve for x and y : `\frac { ax }{ b } – \frac { by }{ a } = a + b ; ax – by = 2ab`
Solve the following pair of linear equation by the elimination method and the substitution method:
3x + 4y = 10 and 2x – 2y = 2
Solve the following pair of linear equation by the elimination method and the substitution method.
`x/2 + (2y)/3 = -1 and x - y /3 = 3`
Out of 1900 km, Vishal travelled some distance by bus and some by aeroplane. The bus travels with an average speed of 60 km/hr and the average speed of the aeroplane is 700 km/hr. It takes 5 hours to complete the journey. Find the distance, Vishal travelled by bus.
Ajay is younger than Vijay by 5 years. Sum of their ages is 25 years. What is Ajay's age?
If the length of a rectangle is reduced by 5 units and its breadth is increased by 3 units, then the area of the rectangle is reduced by 9 square units. If length is reduced by 3 units and breadth is increased by 2 units, then the area of rectangle will increase by 67 square units. Then find the length and breadth of the rectangle.
Solve the following simultaneous equation.
x - 2y = -1 ; 2x - y = 7
Solve the following simultaneous equation.
x − 2y = −2 ; x + 2y = 10
By equating coefficients of variables, solve the following equation.
4x + y = 34 ; x + 4y = 16
Complete the activity.

The sum of the two-digit number and the number obtained by interchanging the digits is 132. The digit in the ten’s place is 2 more than the digit in the unit’s place. Complete the activity to find the original number.
Activity: Let the digit in the unit’s place be y and the digit in the ten’s place be x.
∴ The number = 10x + y
∴ The number obtained by interchanging the digits = `square`
∴ The sum of the number and the number obtained by interchanging the digits = 132
∴ 10x + y + 10y + x = `square`
∴ x + y = `square` .....(i)
By second condition,
Digit in the ten’s place = digit in the unit’s place + 2
∴ x – y = 2 ......(ii)
Solving equations (i) and (ii)
∴ x = `square`, y = `square`
Ans: The original number = `square`
Difference between two numbers is 3. The sum of three times the bigger number and two times the smaller number is 19. Then find the numbers
The angles of a triangle are x, y and 40°. The difference between the two angles x and y is 30°. Find x and y.
