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Question
Sanjay gets fixed monthly income. Every year there is a certain increment in his salary. After 4 years, his monthly salary was Rs. 4500 and after 10 years his monthly salary became 5400 rupees, then find his original salary and yearly increment.
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Solution
Let the fixed monthly income be Rs x.
Annual increment be Rs y.
After 4 years, his monthly salary was Rs. 4500
Monthly salary + annual increment of 4 years = 4500
x + 4y = 4500 ...(I)
After 10 years his monthly salary became 5400 rupees
Monthly salary + annual increment of 10 years = 5400
x + 10y = 5400 ...(II)
Subtracting I from II
x + 4y = 4500
x + 10y = 5400
− − −
−6y = −900
∴ y = 150
put y = 150 in equation (I)
x + 4y = 4500
x + 4 × 150 = 4500
x + 600 = 4500
x = 4500 − 600
x = 3900
Thus, the monthly salary = Rs. 3900
Annual increment = Rs.150
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