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Solve the following quadratic equations by factorization: ax2 + (4a2 − 3b)x − 12ab = 0

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Question

Solve the following quadratic equations by factorization:

ax2 + (4a2 − 3b)x − 12ab = 0

Sum
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Solution

Given:

ax2 + (4a2 − 3b)x − 12ab = 0

ax2 + 4a2x − 3bx − 12ab = 0

ax(x + 4a) − 3b(x + 4a) = 0

(ax − 3b) (x + 4a) = 0

Therefore,

ax − 3b = 0

ax = 3b

`x=(3b)/a`

or

x + 4a = 0

x = −4a

Hence, `x=(3b)/a` or x = −4a

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Chapter 5: Quadratic equations - Exercise 5B [Page 64]

APPEARS IN

Nootan Mathematics [English] Class 10 ICSE
Chapter 5 Quadratic equations
Exercise 5B | Q 9. | Page 64
R.D. Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.3 | Q 19 | Page 19

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