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Question
Solve the following quadratic equations by factorization:
ax2 + (4a2 − 3b)x − 12ab = 0
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Solution
Given:
ax2 + (4a2 − 3b)x − 12ab = 0
ax2 + 4a2x − 3bx − 12ab = 0
ax(x + 4a) − 3b(x + 4a) = 0
(ax − 3b) (x + 4a) = 0
Therefore,
ax − 3b = 0
ax = 3b
`x=(3b)/a`
or
x + 4a = 0
x = −4a
Hence, `x=(3b)/a` or x = −4a
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