Advertisements
Advertisements
Question
Solve the following quadratic equations by factorization:
ax2 + (4a2 − 3b)x − 12ab = 0
Advertisements
Solution
Given:
ax2 + (4a2 − 3b)x − 12ab = 0
ax2 + 4a2x − 3bx − 12ab = 0
ax(x + 4a) − 3b(x + 4a) = 0
(ax − 3b) (x + 4a) = 0
Therefore,
ax − 3b = 0
ax = 3b
`x=(3b)/a`
or
x + 4a = 0
x = −4a
Hence, `x=(3b)/a` or x = −4a
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equation by Factorisation method: x2 + 7x + 10 = 0
Solve (i) x2 + 3x – 18 = 0
(ii) (x – 4) (5x + 2) = 0
(iii) 2x2 + ax – a2 = 0; where ‘a’ is a real number
John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.
If y = 1 is a common root of the equations \[a y^2 + ay + 3 = 0 \text { and } y^2 + y + b = 0\], then ab equals
Solve the following equation: `("x" + 3)/("x" - 2) - (1 - "x")/"x" = 17/4`
Solve equation using factorisation method:
`2x^2 - 1/2x = 0`
The sum of the squares of three consecutive natural numbers is 110. Determine the numbers.
Solve the following quadratic equation by factorisation:
x2 + 3x - 18 = 0
Solve the following equation by factorization
`x + (1)/x = 2(1)/(20)`
(x – 3) (x + 5) = 0 gives x equal to ______.
