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Question
\[\frac{\sin \theta}{1 + \cos \theta}\]is equal to
Options
\[\frac{\sin \theta}{1 + \cos \theta}\]
\[\frac{1 - \cos \theta}{\cos \theta}\]
\[\frac{1 - \cos \theta}{\cos \theta}\]
\[\frac{1 - \sin \theta}{\cos \theta}\]
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Solution
The given expression is `sin θ/(1+cosθ)`
Multiplying both the numerator and denominator under the root by`(1-cosθ )` , we have
`sinθ/(1+cos θ)`
= `(sinθ (1-cos θ))/((1+cosθ)(1-cos θ))`
=`(sin θ(1-cos θ))/(1-cos^2 θ)`
= `(sin θ(1-cos θ))/sin^2 θ`
= `(1-cos θ)/sin θ`
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