English

1 − Sin θ Cos θ is Equal to - Mathematics

Advertisements
Advertisements

Question

\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to

Options

  •  0

  • 1

  • sin θ + cos θ

  • sin θ − cos θ

MCQ
Advertisements

Solution

The given expression is ` sin θ/(1-cot θ)+ cos θ/(1-tan θ)` 

Simplifying the given expression, we have 

`sin θ/(1-cot θ)+ cos θ/(1-tan θ)` 

= `sinθ/(1-cosθ/sinθ)+cos θ/(1-sinθ/cos θ)`

=` sin θ/((sinθ-cos θ)/sin θ)+cos θ/((cos θ-sin θ)/cos θ)` 

= `sin^2θ/(sin θ-cos θ)+cos^2θ/(cos θ-sin θ)` 

= `sin^2θ/(sin θ-cos θ)+cos ^2θ/(-1(sin θ-cos θ))` 

= `sin ^2θ/(sin θ-cos θ)-cos ^2 θ/(sin θ-cos θ)` 

= `(sin^2θ-cos^2θ)/(sin θ-cos θ)` 

=` ((sinθ+cos θ)(sinθ-cos θ))/(sin θ-cos θ)`

=` sin θ+cos θ`

shaalaa.com
  Is there an error in this question or solution?
Chapter 11: Trigonometric Identities - Exercise 11.4 [Page 57]

APPEARS IN

RD Sharma Mathematics [English] Class 10
Chapter 11 Trigonometric Identities
Exercise 11.4 | Q 8 | Page 57

RELATED QUESTIONS

Prove the following trigonometric identities.

sec A (1 − sin A) (sec A + tan A) = 1


Prove the following trigonometric identities.

`(1 + sin theta)/cos theta + cos theta/(1 + sin theta) = 2 sec theta`


Prove the following trigonometric identity:

`sqrt((1 + sin A)/(1 - sin A)) = sec A + tan A`


Prove the following trigonometric identities.

`(cot^2 A(sec A - 1))/(1 + sin A) = sec^2 A ((1 - sin A)/(1 + sec A))`


Prove the following trigonometric identities.

`cot^2 A cosec^2B - cot^2 B cosec^2 A = cot^2 A - cot^2 B`


Prove the following identities:

`sqrt((1 - cosA)/(1 + cosA)) = cosec A - cot A`


The value of (1 + cot θ − cosec θ) (1 + tan θ + sec θ) is 


If cos  \[9\theta\] = sin \[\theta\] and  \[9\theta\]  < 900 , then the value of tan \[6 \theta\] is


If secθ + tanθ = m , secθ - tanθ = n , prove that mn = 1


Prove that:

tan (55° + x) = cot (35° – x)


If sin θ = `1/2`, then find the value of θ. 


If cosθ = `5/13`, then find sinθ. 


Prove that (sin θ + cosec θ)2 + (cos θ + sec θ)2 = 7 + tanθ + cotθ. 


There are two poles, one each on either bank of a river just opposite to each other. One pole is 60 m high. From the top of this pole, the angle of depression of the top and foot of the other pole are 30° and 60° respectively. Find the width of the river and height of the other pole.


Prove that ( 1 + tan A)2 + (1 - tan A)2 = 2 sec2A


Without using the trigonometric table, prove that
cos 1°cos 2°cos 3° ....cos 180° = 0.


Prove the following identities: cot θ - tan θ = `(2 cos^2 θ - 1)/(sin θ cos θ)`.


Prove that

sec2A – cosec2A = `(2sin^2"A" - 1)/(sin^2"A"*cos^2"A")`


If cosec θ + cot θ = p, then prove that cos θ = `(p^2 - 1)/(p^2 + 1)`


Prove that `sqrt(sec^2 theta + "cosec"^2 theta) = tan theta + cot theta`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×