Advertisements
Advertisements
प्रश्न
\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to
विकल्प
0
1
sin θ + cos θ
sin θ − cos θ
Advertisements
उत्तर
The given expression is ` sin θ/(1-cot θ)+ cos θ/(1-tan θ)`
Simplifying the given expression, we have
`sin θ/(1-cot θ)+ cos θ/(1-tan θ)`
= `sinθ/(1-cosθ/sinθ)+cos θ/(1-sinθ/cos θ)`
=` sin θ/((sinθ-cos θ)/sin θ)+cos θ/((cos θ-sin θ)/cos θ)`
= `sin^2θ/(sin θ-cos θ)+cos^2θ/(cos θ-sin θ)`
= `sin^2θ/(sin θ-cos θ)+cos ^2θ/(-1(sin θ-cos θ))`
= `sin ^2θ/(sin θ-cos θ)-cos ^2 θ/(sin θ-cos θ)`
= `(sin^2θ-cos^2θ)/(sin θ-cos θ)`
=` ((sinθ+cos θ)(sinθ-cos θ))/(sin θ-cos θ)`
=` sin θ+cos θ`
APPEARS IN
संबंधित प्रश्न
Without using trigonometric tables evaluate
`(sin 35^@ cos 55^@ + cos 35^@ sin 55^@)/(cosec^2 10^@ - tan^2 80^@)`
Prove the following trigonometric identities
`cos theta/(1 - sin theta) = (1 + sin theta)/cos theta`
Prove the following trigonometric identities.
`(1 + sin θ)/cos θ+ cos θ/(1 + sin θ) = 2 sec θ`
Prove that:
`1/(cosA + sinA - 1) + 1/(cosA + sinA + 1) = cosecA + secA`
If x = r sin A cos B, y = r sin A sin B and z = r cos A, then prove that : x2 + y2 + z2 = r2
`(tan theta)/((sec theta -1))+(tan theta)/((sec theta +1)) = 2 sec theta`
`(sin theta)/((sec theta + tan theta -1)) + cos theta/((cosec theta + cot theta -1))=1`
Write the value of `( 1- sin ^2 theta ) sec^2 theta.`
Find the value of sin ` 48° sec 42° + cos 48° cosec 42°`
Write True' or False' and justify your answer the following :
The value of the expression \[\sin {80}^° - \cos {80}^°\]
If `x/(a cosθ) = y/(b sinθ) "and" (ax)/cosθ - (by)/sinθ = a^2 - b^2 , "prove that" x^2/a^2 + y^2/b^2 = 1`
If x = acosθ , y = bcotθ , prove that `a^2/x^2 - b^2/y^2 = 1.`
Prove that (sin θ + cosec θ)2 + (cos θ + sec θ)2 = 7 + tan2 θ + cot2 θ.
Prove that `((1 + sin θ - cos θ)/( 1 + sin θ + cos θ))^2 = (1 - cos θ)/(1 + cos θ)`.
cot θ . tan θ = ?
Prove that `sec^2A - "cosec"^2A = (2sin^2A - 1)/(sin^2A *cos^2A)`.
If 5 tan β = 4, then `(5 sin β - 2 cos β)/(5 sin β + 2 cos β)` = ______.
Let α, β be such that π < α – β < 3π. If sin α + sin β = `-21/65` and cos α + cos β = `-27/65`, then the value of `cos (α - β)/2` is ______.
`(cos^2 θ)/(sin^2 θ) - 1/(sin^2 θ)`, in simplified form, is ______.
