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Sin θ 1 + Cos θ is Equal to - Mathematics

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प्रश्न

\[\frac{\sin \theta}{1 + \cos \theta}\]is equal to 

विकल्प

  • \[\frac{\sin \theta}{1 + \cos \theta}\]

  • \[\frac{1 - \cos \theta}{\cos \theta}\]

  • \[\frac{1 - \cos \theta}{\cos \theta}\]

  • \[\frac{1 - \sin \theta}{\cos \theta}\]

MCQ
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उत्तर

The given expression is `sin θ/(1+cosθ)`  

Multiplying both the numerator and denominator under the root by`(1-cosθ )` , we have 

`sinθ/(1+cos θ)`  

= `(sinθ (1-cos θ))/((1+cosθ)(1-cos θ))` 

=`(sin θ(1-cos θ))/(1-cos^2 θ)` 

= `(sin θ(1-cos θ))/sin^2 θ` 

= `(1-cos θ)/sin θ` 

 

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Trigonometric Identities - Exercise 11.4 [पृष्ठ ५७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
अध्याय 11 Trigonometric Identities
Exercise 11.4 | Q 7 | पृष्ठ ५७

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