Advertisements
Advertisements
प्रश्न
\[\frac{\sin \theta}{1 + \cos \theta}\]is equal to
पर्याय
\[\frac{\sin \theta}{1 + \cos \theta}\]
\[\frac{1 - \cos \theta}{\cos \theta}\]
\[\frac{1 - \cos \theta}{\cos \theta}\]
\[\frac{1 - \sin \theta}{\cos \theta}\]
MCQ
Advertisements
उत्तर
The given expression is `sin θ/(1+cosθ)`
Multiplying both the numerator and denominator under the root by`(1-cosθ )` , we have
`sinθ/(1+cos θ)`
= `(sinθ (1-cos θ))/((1+cosθ)(1-cos θ))`
=`(sin θ(1-cos θ))/(1-cos^2 θ)`
= `(sin θ(1-cos θ))/sin^2 θ`
= `(1-cos θ)/sin θ`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
