Advertisements
Advertisements
प्रश्न
Prove that:
`(sin^2θ)/(cosθ) + cosθ = secθ`
Advertisements
उत्तर
LHS = `(sin^2θ)/(cosθ) + cosθ = secθ`
= `(sin^2θ + cos^2θ)/(cosθ)`
= `1/(cosθ)` ...(sin2θ + cos2θ = 1)
= secθ ...`(1/cosθ = secθ)`
R.H.S
LHS = RHS
Hence proved.
संबंधित प्रश्न
If acosθ – bsinθ = c, prove that asinθ + bcosθ = `\pm \sqrt{a^{2}+b^{2}-c^{2}`
Show that `sqrt((1-cos A)/(1 + cos A)) = sinA/(1 + cosA)`
Prove the following trigonometric identities.
`((1 + tan^2 theta)cot theta)/(cosec^2 theta) = tan theta`
If a cos θ + b sin θ = m and a sin θ – b cos θ = n, prove that a2 + b2 = m2 + n2
Prove the following identities:
`cosecA + cotA = 1/(cosecA - cotA)`
Prove the following identities:
`secA/(secA + 1) + secA/(secA - 1) = 2cosec^2A`
`sec theta (1- sin theta )( sec theta + tan theta )=1`
Write the value of `(1 + cot^2 theta ) sin^2 theta`.
Prove that secθ + tanθ =`(costheta)/(1-sintheta)`.
What is the value of \[6 \tan^2 \theta - \frac{6}{\cos^2 \theta}\]
The value of (1 + cot θ − cosec θ) (1 + tan θ + sec θ) is
prove that `1/(1 + cos(90^circ - A)) + 1/(1 - cos(90^circ - A)) = 2cosec^2(90^circ - A)`
Prove that ( 1 + tan A)2 + (1 - tan A)2 = 2 sec2A
Prove that `(sin (90° - θ))/cos θ + (tan (90° - θ))/cot θ + (cosec (90° - θ))/sec θ = 3`.
Prove that cos θ sin (90° - θ) + sin θ cos (90° - θ) = 1.
a cot θ + b cosec θ = p and b cot θ + a cosec θ = q then p2 – q2 is equal to
Choose the correct alternative:
cot θ . tan θ = ?
Prove that `(sin^2theta)/(cos theta) + cos theta` = sec θ
If tan θ = 3, then `(4 sin theta - cos theta)/(4 sin theta + cos theta)` is equal to ______.
(1 + sin A)(1 – sin A) is equal to ______.
