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`Tan Theta/(1+ Tan^2 Theta)^2 + Cottheta/(1+ Cot^2 Theta)^2 = Sin Theta Cos Theta` - Mathematics

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`tan theta/(1+ tan^2 theta)^2 + cottheta/(1+ cot^2 theta)^2 = sin theta cos theta`

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ЁЭР┐ЁЭР╗ЁЭСЖ = `(tan theta)/(1+tan^2 theta )^2 +( cot theta )/(1+cot^2 theta)^2`

        =`tan theta/ ((sec^2  theta)^2) + cot theta/((cosec^2  theta) ^2)`

        =`tan theta / sec^4 theta + cottheta/(cosec^4  theta)`

        =`sin theta/cos theta xx cos^4 theta + cos theta/sin theta xx sin ^4 theta`

      =` sin  theta  cos  ^3 theta + cos theta sin  ^3 theta`

     =`sin theta cos theta ( cos^2 theta + sin ^2 theta)`

    =`sin theta cos theta`

    = RHS

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рдкрд╛рда 8: Trigonometric Identities - Exercises 1

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Prove the following identities, where the angles involved are acute angles for which the expressions are defined:

`sqrt((1+sinA)/(1-sinA)) = secA + tanA`


Prove the following trigonometric identities

(1 + cot2 A) sin2 A = 1


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`(tanA + 1/cosA)^2 + (tanA - 1/cosA)^2 = 2((1 + sin^2A)/(1 - sin^2A))`


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Sin4θ - cos4θ = 1 - 2cos2θ


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`(secθ - tanθ)^2 = (1 - sinθ)/(1 + sinθ)`


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`tan^2θ/(tan^2θ - 1) + (cosec^2θ)/(sec^2θ - cosec^2θ) = 1/(sin^2θ - cos^2θ)`


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`(tanθ + sinθ)/(tanθ - sinθ) = (secθ + 1)/(secθ - 1)`


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