मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

(sec θ + tan θ) . (sec θ – tan θ) = ?

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प्रश्न

(sec θ + tan θ) . (sec θ – tan θ) = ?

बेरीज
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उत्तर

(sec θ + tan θ)(sec θ – tan θ)

= sec2θ – tan2θ   ...[∵ (a + b)(a – b) = a2 – b2]

= 1   ...`[(∵ 1 + tan^2θ = sec^2θ),(∴ sec^2θ - tan^2θ = 1)]`

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पाठ 6: Trigonometry - Exercise

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