Question

If `cos theta = 2/3 , "write the value of" ((sec theta -1))/((sec theta +1))`

Answer 1

`(sec theta -1)/( sec theta +1)`

      = `((1/cos theta - 1/1))/((1/ costheta + 1/1))`

      =`(((1- cos theta)/cos theta))/(((1+ cos theta)/cos theta))`

     =`(1- cos theta)/(1+ cos theta)`

    =`((1/1-2/3))/((1/1+2/3)`

    =`((1/3))/((5/3))`

    =`1/5`