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प्रश्न
What is the value of (1 + cot2 θ) sin2 θ?
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उत्तर
We have,
`(1+cot^2 θ)sin^2θ= cosec^2θxxsin^2θ`
`= (1/sinθ)^2 xx sin^2θ`
= `1/sin^2θxxsin^2θ`
`=1`
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Activity:
L.H.S = `square`
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