मराठी

`Costheta/((1-tan Theta))+Sin^2theta/((Cos Theta-sintheta))=(Cos Theta+ Sin Theta)` - Mathematics

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प्रश्न

`costheta/((1-tan theta))+sin^2theta/((cos theta-sintheta))=(cos theta+ sin theta)`

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उत्तर

LHS = `cos theta/((1-tan theta))-sin^2theta/((cos theta-sintheta))`

       =`cos theta/((1-sintheta/costheta)) -sin^2 theta/((cos theta-sin theta))`

     =`cos^2 theta/((cos theta-sintheta))- sin^2 theta/((cos theta-sin theta))`

     =`(cos^2 theta- sin ^2 theta)/((cos theta- sin theta))`

    =`((costheta + sin theta)( cos theta-sin theta))/((cos theta - sin theta))`

   =`(cos theta + sin theta)`

   = RHS
Hence, LHS = RHS

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पाठ 8: Trigonometric Identities - Exercises 1

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 8 Trigonometric Identities
Exercises 1 | Q 14

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