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प्रश्न
If `cos θ = 24/25`, then sin θ = ?
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उत्तर
`cos θ = 24/25` ...[Given]
We know that,
sin2θ + cos2θ = 1
∴ `sin^2θ + (24/25)^2 = 1`
∴ `sin^2θ + 576/625 = 1`
∴ `sin^2θ = 1 - 576/625`
∴ `sin^2θ = (625 - 576)/625`
∴ `sin^2θ = 49/625`
∴ `sin θ = 7/25` ...[Taking square root of both sides]
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संबंधित प्रश्न
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`(sec theta -1 )/( sec theta +1) = ( sin ^2 theta)/( (1+ cos theta )^2)`
`(1+ tan theta + cot theta )(sintheta - cos theta) = ((sec theta)/ (cosec^2 theta)-( cosec theta)/(sec^2 theta))`
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Activity:
sec2θ = 1 + `square` ...[Fundamental tri. identity]
sec2θ = 1 + `square^2`
sec2θ = 1 + `square/576`
sec2θ = `square/576`
sec θ = `square`
cos θ = `square ...`[cos theta = 1/sectheta]`
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