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प्रश्न
Prove that `(sin^2θ)/(cos θ) + cos θ = sec θ`.
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उत्तर
L.H.S. = `(sin^2θ)/(cos θ) + cos θ`
= `(sin^2θ + cos^2θ)/(cos θ)`
= `1/(cos θ)` ...[∵ sin2θ + cos2θ = 1]
= sec θ
= R.H.S.
∴ `(sin^2θ)/(cos θ) + cos θ = sec θ`
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