Advertisements
Advertisements
प्रश्न
Prove the following identity :
secA(1 - sinA)(secA + tanA) = 1
Advertisements
उत्तर
LHS = secA(1 - sinA)(secA + tanA)
= `1/cosA(1-sinA)(1/cosA + sinA/cosA)`
= `((1 -sinA))/cosA((1 + sinA)/cosA) = ((1 - sin^2A)/cos^2A)`
= `(cos^2A/cos^2A)`
= 1 = RHS
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities
cosec6θ = cot6θ + 3 cot2θ cosec2θ + 1
Prove the following trigonometric identities.
if `T_n = sin^n theta + cos^n theta`, prove that `(T_3 - T_5)/T_1 = (T_5 - T_7)/T_3`
`(cot ^theta)/((cosec theta+1)) + ((cosec theta + 1))/cot theta = 2 sec theta`

From the figure find the value of sinθ.
Without using trigonometric identity , show that :
`tan10^circ tan20^circ tan30^circ tan70^circ tan80^circ = 1/sqrt(3)`
Prove that sin4θ - cos4θ = sin2θ - cos2θ
= 2sin2θ - 1
= 1 - 2 cos2θ
If cosθ + sinθ = `sqrt2` cosθ, show that cosθ - sinθ = `sqrt2` sinθ.
Prove that `sintheta/(sectheta+ 1) +sintheta/(sectheta - 1)` = 2 cot θ
Prove that `sqrt((1 + cos "A")/(1 - cos"A"))` = cosec A + cot A
tan θ × `sqrt(1 - sin^2 θ)` is equal to:
