Advertisements
Advertisements
प्रश्न
Prove the following identity :
secA(1 - sinA)(secA + tanA) = 1
Advertisements
उत्तर
LHS = secA(1 - sinA)(secA + tanA)
= `1/cosA(1-sinA)(1/cosA + sinA/cosA)`
= `((1 -sinA))/cosA((1 + sinA)/cosA) = ((1 - sin^2A)/cos^2A)`
= `(cos^2A/cos^2A)`
= 1 = RHS
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities
(1 + cot2 A) sin2 A = 1
Prove the following identities:
(1 + tan A + sec A) (1 + cot A – cosec A) = 2
If `(cot theta ) = m and ( sec theta - cos theta) = n " prove that " (m^2 n)(2/3) - (mn^2)(2/3)=1`
If`( 2 sin theta + 3 cos theta) =2 , " prove that " (3 sin theta - 2 cos theta) = +- 3.`
If tan A =` 5/12` , find the value of (sin A+ cos A) sec A.

From the figure find the value of sinθ.
\[\frac{\tan \theta}{\sec \theta - 1} + \frac{\tan \theta}{\sec \theta + 1}\] is equal to
Prove that (sin θ + cosec θ)2 + (cos θ + sec θ)2 = 7 + tan2 θ + cot2 θ.
If A = 30°, verify that `sin 2A = (2 tan A)/(1 + tan^2 A)`.
If cos A + cos2A = 1, then sin2A + sin4 A = ?
