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प्रश्न
`1/((1+tan^2 theta)) + 1/((1+ tan^2 theta))`
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उत्तर
LHS=` 1/((1+ tan^2 theta))+1/((1+ cot^2 theta))`
=`1/sec^2 theta + 1/(cosec^2 theta)`
=` cos^2 theta + sin^2 theta`
=1
=RHS
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संबंधित प्रश्न
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Solution :
L.H.S. = cotθ + tanθ
= `cosθ/sinθ + sinθ/cosθ`
= `(square + square)/(sinθ xx cosθ)`
= `1/(sinθ xx cosθ)` ............... `square`
= `1/sinθ xx 1/square`
= cosecθ × secθ
L.H.S. = R.H.S
∴ cotθ + tanθ = cosecθ × secθ
Statement 1: sin2θ + cos2θ = 1
Statement 2: cosec2θ + cot2θ = 1
Which of the following is valid?
