मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

If Tanθ = 3 4 Then Find the Value of Secθ.

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प्रश्न

If tanθ `= 3/4` then find the value of secθ.

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उत्तर

If tanθ = 34
1 + tan2θ = sec2θ

∴ 1 + `(3/4)^2= sec^2θ`

∴ `1 + 9/16 = sec^2θ`

∴ `25/16 = sec^2θ`

∴ `secθ = 5/4`

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2018-2019 (March) Balbharati Model Question Paper Set 2

संबंधित प्रश्‍न

If tanθ + sinθ = m and tanθ – sinθ = n, show that `m^2 – n^2 = 4\sqrt{mn}.`


 
 

Prove the following identities, where the angles involved are acute angles for which the expressions are defined:

`(1+ secA)/sec A = (sin^2A)/(1-cosA)` 

[Hint : Simplify LHS and RHS separately.]

 
 

Prove the following trigonometric identities.

if `T_n = sin^n theta + cos^n theta`, prove that `(T_3 - T_5)/T_1 = (T_5 - T_7)/T_3`


Prove the following identities:

`(sec A - 1)/(sec A + 1) = (1 - cos A)/(1 + cos A)`


Prove the following identities:

`(1 - sinA)/(1 + sinA) = (secA - tanA)^2`


Prove that:

`(sinA - sinB)/(cosA + cosB) + (cosA - cosB)/(sinA + sinB) = 0`


Prove that:

cos A (1 + cot A) + sin A (1 + tan A) = sec A + cosec A


`(1+tan^2theta)(1+cot^2 theta)=1/((sin^2 theta- sin^4theta))`


Prove that `( sintheta - 2 sin ^3 theta ) = ( 2 cos ^3 theta - cos theta) tan theta`


\[\frac{\sin \theta}{1 + \cos \theta}\]is equal to 


If a cos θ + b sin θ = m and a sin θ − b cos θ = n, then a2 + b2 =


The value of sin ( \[{45}^° + \theta) - \cos ( {45}^°- \theta)\] is equal to 


If secθ + tanθ = m , secθ - tanθ = n , prove that mn = 1


Without using trigonometric identity , show that :

`cos^2 25^circ + cos^2 65^circ = 1`


Prove that  `sin^2 θ/ cos^2 θ + cos^2 θ/sin^2 θ = 1/(sin^2 θ. cos^2 θ) - 2`.


Prove the following identities:

`(1 - tan^2 θ)/(cot^2 θ - 1) = tan^2 θ`.


If x sin3 θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ, then prove that x2 + y2 = 1


Prove that `(1 + sin θ)/(1 - sin θ) = (sec θ + tan θ)^2`.


The value of 2sinθ can be `a + 1/a`, where a is a positive number, and a ≠ 1.


Prove that `(1 + sec theta - tan theta)/(1 + sec theta + tan theta) = (1 - sin theta)/cos theta`


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