Advertisements
Advertisements
प्रश्न
Prove that:
`cot^2A/(cosecA - 1) - 1 = cosecA`
Advertisements
उत्तर
`cot^2A/(cosecA - 1) - 1`
= `(cot^2A - cosecA + 1)/(cosecA - 1)`
= `(-cosecA + cosec^2A)/(cosecA - 1)`
= `(cosecA(cosecA - 1))/(cosecA - 1)`
= cosec A
APPEARS IN
संबंधित प्रश्न
9 sec2 A − 9 tan2 A = ______.
`Prove the following trigonometric identities.
`(sec A - tan A)^2 = (1 - sin A)/(1 + sin A)`
Prove the following trigonometric identities.
tan2 A sec2 B − sec2 A tan2 B = tan2 A − tan2 B
Prove the following identities:
`(1 + (secA - tanA)^2)/(cosecA(secA - tanA)) = 2tanA`
(i)` (1-cos^2 theta )cosec^2theta = 1`
`cot theta/((cosec theta + 1) )+ ((cosec theta +1 ))/ cot theta = 2 sec theta `
If \[\sin \theta = \frac{1}{3}\] then find the value of 9tan2 θ + 9.
Without using trigonometric table , evaluate :
`(sin47^circ/cos43^circ)^2 - 4cos^2 45^circ + (cos43^circ/sin47^circ)^2`
The value of sin2θ + `1/(1 + tan^2 theta)` is equal to
Prove that `(sin^2θ)/(cos θ) + cos θ = sec θ`.
