Advertisements
Advertisements
प्रश्न
Prove that:
`cot^2A/(cosecA - 1) - 1 = cosecA`
Advertisements
उत्तर
`cot^2A/(cosecA - 1) - 1`
= `(cot^2A - cosecA + 1)/(cosecA - 1)`
= `(-cosecA + cosec^2A)/(cosecA - 1)`
= `(cosecA(cosecA - 1))/(cosecA - 1)`
= cosec A
APPEARS IN
संबंधित प्रश्न
Prove the following identities:
`(cotA - cosecA)^2 = (1 - cosA)/(1 + cosA)`
Prove the following identities:
`cotA/(1 - tanA) + tanA/(1 - cotA) = 1 + tanA + cotA`
`1+((tan^2 theta) cot theta)/(cosec^2 theta) = tan theta`
`sin theta / ((1+costheta))+((1+costheta))/sin theta=2cosectheta`
` (sin theta + cos theta )/(sin theta - cos theta ) + ( sin theta - cos theta )/( sin theta + cos theta) = 2/ ((1- 2 cos^2 theta))`
Prove the following identity :
`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`
Evaluate:
`(tan 65^circ)/(cot 25^circ)`
Prove the following identities: cot θ - tan θ = `(2 cos^2 θ - 1)/(sin θ cos θ)`.
Prove that: `1/(sec θ - tan θ) = sec θ + tan θ`.
If 3 sin A + 5 cos A = 5, then show that 5 sin A – 3 cos A = ± 3.
