Advertisements
Advertisements
प्रश्न
Prove that:
`cosA/(1 + sinA) = secA - tanA`
Advertisements
उत्तर
`cosA/(1+sinA)`
= `cosA/(1 + sinA) xx (1 - sinA)/(1 - sinA)`
= `(cosA(1 - sinA))/(1 - sin^2A)`
= `(cosA(1 - sinA))/(cos^2A)`
= `(1-sinA)/cosA`
= sec A – tan A
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities.
`tan θ/(1 - cot θ) + cot θ/(1 - tan θ) = 1 + tan θ + cot θ`
Prove the following trigonometric identities.
`((1 + tan^2 theta)cot theta)/(cosec^2 theta) = tan theta`
Prove the following trigonometric identities.
`1/(sec A - 1) + 1/(sec A + 1) = 2 cosec A cot A`
Prove the following trigonometric identities.
(sec A + tan A − 1) (sec A − tan A + 1) = 2 tan A
If cos θ + cot θ = m and cosec θ – cot θ = n, prove that mn = 1
If sin A + cos A = m and sec A + cosec A = n, show that : n (m2 – 1) = 2 m
Write the value of `sin theta cos ( 90° - theta )+ cos theta sin ( 90° - theta )`.
Prove that `( 1 + sin θ)/(1 - sin θ) = 1 + 2 tan θ/cos θ + 2 tan^2 θ` .
Prove that `(sin θ + "cosec" θ)/(sin θ) = 2 + cot^2θ`.
Which of the following is true for all values of θ (0° ≤ θ ≤ 90°)?
