Advertisements
Advertisements
प्रश्न
Prove that:
`cosA/(1 + sinA) = secA - tanA`
Advertisements
उत्तर
`cosA/(1+sinA)`
= `cosA/(1 + sinA) xx (1 - sinA)/(1 - sinA)`
= `(cosA(1 - sinA))/(1 - sin^2A)`
= `(cosA(1 - sinA))/(cos^2A)`
= `(1-sinA)/cosA`
= sec A – tan A
APPEARS IN
संबंधित प्रश्न
`"If "\frac{\cos \alpha }{\cos \beta }=m\text{ and }\frac{\cos \alpha }{\sin \beta }=n " show that " (m^2 + n^2 ) cos^2 β = n^2`
Prove the following identities:
`((cosecA - cotA)^2 + 1)/(secA(cosecA - cotA)) = 2cotA`
Prove the following identities:
`cot^2A((secA - 1)/(1 + sinA)) + sec^2A((sinA - 1)/(1 + secA)) = 0`
Prove that:
cos A (1 + cot A) + sin A (1 + tan A) = sec A + cosec A
Define an identity.
Write the value of \[\cot^2 \theta - \frac{1}{\sin^2 \theta}\]
If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2?
If sinA + cosA = `sqrt(2)` , prove that sinAcosA = `1/2`
Show that tan 7° × tan 23° × tan 60° × tan 67° × tan 83° = `sqrt(3)`.
(tan θ + 2)(2 tan θ + 1) = 5 tan θ + sec2θ.
