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प्रश्न
Prove that `cos θ/sin(90° - θ) + sin θ/cos (90° - θ) = 2`.
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उत्तर
LHS = `cos θ/sin(90° - θ) + sin θ/cos (90° - θ) `
= `cos θ/cos θ + sin θ/sin θ`
= 1 + 1 = 2
= RHS
Hence proved.
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