हिंदी

If Sin2 θ Cos2 θ (1 + Tan2 θ) (1 + Cot2 θ) = λ, Then Find the Value of λ. - Mathematics

Advertisements
Advertisements

प्रश्न

If sin2 θ cos2 θ (1 + tan2 θ) (1 + cot2 θ) = λ, then find the value of λ. 

योग
Advertisements

उत्तर

Given: 

`sin ^2θ cos^2 θ(1+tan^2 θ)(1+cot ^2θ)=λ`

`⇒ sin^2θ cos^2 θ sec^2 θ cosec^2θ=λ`

⇒`(sin^2 θ cosec^2θ )xx (cos^2θ sec^2 θ)= λ` 

⇒ `(sin^2θ xx 1/sin^2θ )(cos^2 θxx1/cos^2θ)=λ`

\[\Rightarrow \lambda = 1 \times 1 = 1\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Trigonometric Identities - Exercise 11.3 [पृष्ठ ५५]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
अध्याय 11 Trigonometric Identities
Exercise 11.3 | Q 21 | पृष्ठ ५५

संबंधित प्रश्न

Prove that `cosA/(1+sinA) + tan A =  secA`


Prove the following trigonometric identities

(1 + cot2 A) sin2 A = 1


If x = a sec θ cos ϕ, y = b sec θ sin ϕ and z c tan θ, show that `x^2/a^2 + y^2/b^2 - x^2/c^2 = 1`


Prove that:

(sec A − tan A)2 (1 + sin A) = (1 − sin A)


Prove the following identities:

`cotA/(1 - tanA) + tanA/(1 - cotA) = 1 + tanA + cotA`


Prove the following identities:

`cot^2A((secA - 1)/(1 + sinA)) + sec^2A((sinA - 1)/(1 + secA)) = 0`


`sin^6 theta + cos^6 theta =1 -3 sin^2 theta cos^2 theta`


The value of \[\sqrt{\frac{1 + \cos \theta}{1 - \cos \theta}}\]


Simplify 

sin A `[[sinA   -cosA],["cos A"  " sinA"]] + cos A[[ cos A" sin A " ],[-sin A" cos A"]]`


Prove the following identity :

`(1 - tanA)^2 + (1 + tanA)^2 = 2sec^2A`


Prove the following identity : 

`cosA/(1 - tanA) + sinA/(1 - cotA) = sinA + cosA`


Prove the following identity :

`(sec^2θ - sin^2θ)/tan^2θ = cosec^2θ - cos^2θ`


Without using trigonometric table , evaluate : 

`(sin47^circ/cos43^circ)^2 - 4cos^2 45^circ + (cos43^circ/sin47^circ)^2`


Without using trigonometric table , evaluate : 

`cos90^circ + sin30^circ tan45^circ cos^2 45^circ`


Without using trigonometric identity , show that :

`tan10^circ tan20^circ tan30^circ tan70^circ tan80^circ = 1/sqrt(3)`


If sec θ = x + `1/(4"x"), x ≠ 0,` find (sec θ + tan θ)


`(1 - tan^2 45^circ)/(1 + tan^2 45^circ)` = ?


`5/(sin^2theta) - 5cot^2theta`, complete the activity given below.

Activity:

`5/(sin^2theta) - 5cot^2theta`

= `square (1/(sin^2theta) - cot^2theta)`

= `5(square - cot^2theta)   ......[1/(sin^2theta) = square]`

= 5(1)

= `square`


sin4A – cos4A = 1 – 2cos2A. For proof of this complete the activity given below.

Activity:

L.H.S = `square`

 = (sin2A + cos2A) `(square)`

= `1 (square)`       .....`[sin^2"A" + square = 1]`

= `square` – cos2A    .....[sin2A = 1 – cos2A]

= `square`

= R.H.S


The value of the expression [cosec(75° + θ) – sec(15° – θ) – tan(55° + θ) + cot(35° – θ)] is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×