Advertisements
Advertisements
प्रश्न
Prove the following identity :
`tanA - cotA = (1 - 2cos^2A)/(sinAcosA)`
Advertisements
उत्तर
`tanA - cotA = sinA/cosA - cosA/sinA`
= `(sin^2A - cos^2A)/(sinAcosA)`
= `(1 - cos^2A - cos^2A)/(sinAcosA)` (`Q sin^2A = 1 - cos^2A`)
= `(1 - 2cos^2A)/(sinAcosA)`
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities:
`(1 - cos^2 A) cosec^2 A = 1`
Prove the following trigonometric identity.
`(sin theta - cos theta + 1)/(sin theta + cos theta - 1) = 1/(sec theta - tan theta)`
Prove the following trigonometric identities.
`(cos theta - sin theta + 1)/(cos theta + sin theta - 1) = cosec theta + cot theta`
Prove that:
`(cosecA - sinA)(secA - cosA) = 1/(tanA + cotA)`
Prove the following identities:
`1/(cosA + sinA) + 1/(cosA - sinA) = (2cosA)/(2cos^2A - 1)`
`(tan^2theta)/((1+ tan^2 theta))+ cot^2 theta/((1+ cot^2 theta))=1`
Prove that: sin4 θ + cos4θ = 1 - 2sin2θ cos2 θ.
Choose the correct alternative:
cos 45° = ?
Prove that sec2θ – cos2θ = tan2θ + sin2θ
Prove the following:
`sintheta/(1 + cos theta) + (1 + cos theta)/sintheta` = 2cosecθ
