Advertisements
Advertisements
प्रश्न
Prove the following identity :
`tanA - cotA = (1 - 2cos^2A)/(sinAcosA)`
Advertisements
उत्तर
`tanA - cotA = sinA/cosA - cosA/sinA`
= `(sin^2A - cos^2A)/(sinAcosA)`
= `(1 - cos^2A - cos^2A)/(sinAcosA)` (`Q sin^2A = 1 - cos^2A`)
= `(1 - 2cos^2A)/(sinAcosA)`
APPEARS IN
संबंधित प्रश्न
Prove that
`sqrt((1 + sin θ)/(1 - sin θ)) + sqrt((1 - sin θ)/(1 + sin θ)) = 2 sec θ`
Prove the following identities:
`sqrt((1 - cosA)/(1 + cosA)) = sinA/(1 + cosA)`
If tan A = n tan B and sin A = m sin B, prove that `cos^2A = (m^2 - 1)/(n^2 - 1)`
If `( tan theta + sin theta ) = m and ( tan theta - sin theta ) = n " prove that "(m^2-n^2)^2 = 16 mn .`
What is the value of \[\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}\]
\[\frac{\tan \theta}{\sec \theta - 1} + \frac{\tan \theta}{\sec \theta + 1}\] is equal to
Prove the following identity :
cosecθ(1 + cosθ)(cosecθ - cotθ) = 1
Prove that: 2(sin6θ + cos6θ) - 3 ( sin4θ + cos4θ) + 1 = 0.
Prove that `cos θ/sin(90° - θ) + sin θ/cos (90° - θ) = 2`.
If 5 tan β = 4, then `(5 sin β - 2 cos β)/(5 sin β + 2 cos β)` = ______.
