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If cos (α + β) = 0, then sin (α – β) can be reduced to ______. - Mathematics

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प्रश्न

If cos (α + β) = 0, then sin (α – β) can be reduced to ______.

विकल्प

  • cos β

  • cos 2β

  • sin α

  • sin 2α

MCQ
रिक्त स्थान भरें
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उत्तर

If cos (α + β) = 0, then sin (α – β) can be reduced to cos 2β.

Explanation:

According to the question,

cos(α + β) = 0

Since, cos 90° = 0

We can write,

cos(α + β) = cos 90°

By comparing cosine equation on L.H.S and R.H.S,

We get,

(α + β) = 90°

α = 90° – β

Now we need to reduce sin(α – β),

So, we take,

sin(α – β) = sin(90° – β – β) = sin(90° – 2β)

sin(90° – θ) = cos θ

So, sin(90° – 2β) = cos 2β

Therefore, sin(α – β) = cos 2β

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अध्याय 8: Introduction To Trigonometry and Its Applications - Exercise 8.1 [पृष्ठ ९०]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 8 Introduction To Trigonometry and Its Applications
Exercise 8.1 | Q 5 | पृष्ठ ९०

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