हिंदी

Prove that cot^2θ × sec^2θ = cot^2θ + 1.

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प्रश्न

Prove that cot2θ × sec2θ = cot2θ + 1.

प्रमेय
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उत्तर

L.H.S. = cot2θ × sec2θ

= `(cos^2θ)/(sin^2θ) xx 1/(cos^2θ)`

= `1/(sin^2θ)`

= cosec2θ

= 1 + cot2θ   ...[∵ 1 + cot2θ = cosec2θ]

= R.H.S.

∴ cot2θ × sec2θ = cot2θ + 1

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अध्याय 6: Trigonometry - Q.2 (B)

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