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Maharashtra State BoardSSC (English Medium) 10th Standard

Prove that cot^2θ × sec^2θ = cot^2θ + 1.

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Question

Prove that cot2θ × sec2θ = cot2θ + 1.

Theorem
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Solution

L.H.S. = cot2θ × sec2θ

= `(cos^2θ)/(sin^2θ) xx 1/(cos^2θ)`

= `1/(sin^2θ)`

= cosec2θ

= 1 + cot2θ   ...[∵ 1 + cot2θ = cosec2θ]

= R.H.S.

∴ cot2θ × sec2θ = cot2θ + 1

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Chapter 6: Trigonometry - Exercise

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To prove cot θ + tan θ = cosec θ × sec θ, complete the activity given below.

Activity:

L.H.S. = `square`

= `square/(sinθ) + (sinθ)/(cosθ)`

= `(cos^2θ + sin^2θ)/square`

= `1/(sinθ.cosθ)`   ...`[cos^2θ + sin^2θ = square]`

= `1/(sinθ) xx 1/square`

= `square`

= R.H.S.


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