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Prove the following identities: 1-sinA1+sinA=(secA-tanA)2 - Mathematics

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Question

Prove the following identities:

`(1 - sinA)/(1 + sinA) = (secA - tanA)^2`

Sum
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Solution

L.H.S. = `(1 - sinA)/(1 + sinA)`

= `(1 - sinA)/(1 + sinA) xx (1 - sinA)/(1 - sinA)`

= `(1 - sinA)^2/(1 - sin^2A`

= `(1 - sinA)^2/cos^2A`

= `((1 - sinA)/cosA)^2`

= `(1/cosA - sinA/cosA)^2`

= `(secA - tanA)^2`

= R.H.S.

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